{"id":1266,"date":"2015-01-12T18:00:36","date_gmt":"2015-01-12T16:00:36","guid":{"rendered":"http:\/\/mif.vu.lt\/lmma\/?p=1266"},"modified":"2015-01-12T18:00:36","modified_gmt":"2015-01-12T16:00:36","slug":"patikslinta-matematikos-brandos-egzamino-programa","status":"publish","type":"post","link":"https:\/\/www.vu.lt\/lmma\/?p=1266","title":{"rendered":"Patikslinta Matematikos brandos egzamino programa"},"content":{"rendered":"<p><span style=\"font-size: medium;\">\u0160vietimo ir mokslo ministro \u012fsakymu patikslinta <a href=\"http:\/\/www.nec.lt\/375\/\" target=\"_blank\" rel=\"noopener\">Matematikos brandos egzamino programa<\/a>.<!--more--> Pagal patikslint\u0105 Matematikos egzamino program\u0105 <strong>rengiama<\/strong> ir <strong>2015 met\u0173 matematikos valstybinio brandos egzamino u\u017eduotis<\/strong>.<\/span><\/p>\n<p><span style=\"font-size: medium;\">Programoje apibr\u0117\u017etas tikslus egzamino u\u017eduoties ta\u0161k\u0173 skai\u010dius. U\u017eduotyje <\/span><span style=\"font-size: medium;\">bus galima surinkti 60 ta\u0161k\u0173. J\u0105 sud<\/span><span style=\"font-size: medium;\">arys trys dalys:<\/span><\/p>\n<ul>\n<li><span style=\"font-size: medium;\">\u00a0 vien\u0105 u\u017eduoties dal\u012f\u00a0 sudarys 10 u\u017edavini\u0173 su pasirenkamaisiais atsakymais (u\u017e kiekvien\u0105 skiriama po vien\u0105 ta\u0161k\u0105);<\/span><\/li>\n<li><span style=\"font-size: medium;\">antr\u0105 dal\u012f sudarys trumpojo atsakymo (nestrukt\u016bruoti arba strukt\u016bruoti) u\u017edaviniai. J\u0173 turi b\u016bti nuo 4 iki 10 (u\u017edavinys arba jo dalys vertinama 1 ta\u0161ku, vertinamas tik atsakymas). U\u017e antros dalies u\u017edavinius skiriama 12 ta\u0161k\u0173;<\/span><\/li>\n<li><span style=\"font-size: medium;\">tre\u010dioje u\u017eduoties dalyje bus nuo 6 iki 8 u\u017edavini\u0173. Atvirojo atsakymo (strukt\u016bruoti arba nestrukt\u016bruoti) u\u017edaviniai vertinami ne ma\u017eiau kaip 2 ta\u0161kais. I\u0161 viso \u0161i u\u017eduoties dalis vertinama 38 ta\u0161kais.<\/span><\/li>\n<\/ul>\n<p><span style=\"font-size: medium;\"> Taip pat patikslinti reikalavimai mokini\u0173 pasiekimams Matematikos brandos egzamino programos 1 priede ir Matematikos brandos egzamino programos 2 priede pateikta trigonometrini\u0173 funkcij\u0173 reik\u0161mi\u0173 lentel\u0117.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>\u0160vietimo ir mokslo ministro \u012fsakymu patikslinta Matematikos brandos egzamino programa.<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[9],"tags":[],"class_list":["post-1266","post","type-post","status-publish","format-standard","hentry","category-naujienos"],"_links":{"self":[{"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=\/wp\/v2\/posts\/1266","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=1266"}],"version-history":[{"count":0,"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=\/wp\/v2\/posts\/1266\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=1266"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=1266"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.vu.lt\/lmma\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=1266"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}